Calculating Echo Time: 245 Hz Sound Frequency in a 1.41 m Wavelength Canyon

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A 245 Hz sound frequency with a wavelength of 1.41 m results in a wave speed of 345 m/s. To calculate the time for an echo to return from a 1.5 km long canyon, the formula t = d/s is used. By substituting the distance of 1.5 km (1500 m) and the speed of 345 m/s, the time taken for the echo is determined to be approximately 4.35 seconds. The calculations confirm that the echo time is accurate. This process highlights the relationship between frequency, wavelength, and wave speed in sound propagation.
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A 245 Hz sound with a wavelength of 1.41 m is projected into a narrow canyon. If the canyon is 1.50 km long, what time does it take an echo to be heard?

How would I solve for this question? :)
 
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Given the frequency and wavelength, what is the speed of your wave?
 
245[hz] * 1.41[m] = 345 m/s? :)
 
Brittykitty said:
245[hz] * 1.41[m] = 345 m/s? :)

Right, so the wave must travel 1.5 km while traveling at 345 m/s, how would you find the time taken given the distance traveled and the speed?
 
t=d/s
t=1.5km/ 345ms?
t=4.35s?
 
Yes that should be it.
 
Thank you SO much! :D
 
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