Calculating Ek At a specific point

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To calculate the kinetic energy (Ek) at point "B," the potential energy (Ep) at that height is used, specifically the difference in height between points A and B. The formula Ek = m.g.h is applied, where m is mass, g is gravitational acceleration, and h is the height difference. In this case, the height difference is 50 meters, leading to Ek being calculated as 49,000 Joules. The discussion emphasizes that the change in kinetic energy equals the change in potential energy, making the height difference crucial for accurate calculations. Understanding this relationship simplifies the physics problem significantly.
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Homework Statement



I need to find out the Ek at "B" this is the diagram i got i want to know if its right and if it is why do i use the Height of 50 to find out Ek at "B"

phys.jpg


Homework Equations



Ek=Ep

The Attempt at a Solution



Ek=Ep
Ek=m.g.h
Ek=100x9.8x50
Ek=49000J
 
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Welcome to PF!

Hi Articulum! Welcome to PF! :smile:
Articulum said:
I need to find out the Ek at "B" this is the diagram i got i want to know if its right and if it is why do i use the Height of 50 to find out Ek at "B"

Ek=Ep
Ek=m.g.h
Ek=100x9.8x50
Ek=49000J

Yes, that's right! …

(except it's really change in Ek = change in Ep) …

but why were you worried about using 50 for B? :smile:
 


tiny-tim said:
Hi Articulum! Welcome to PF! :smile:


Yes, that's right! …

(except it's really change in Ek = change in Ep) …

but why were you worried about using 50 for B? :smile:

If I'm figuring out Ek at "B" shouldn't i use the height also at "B"?
 
The *change* in kinetic energy plus the *change* in potential energy equals zero here: so you do need to use the height at B, or more precisely, what matters is the *difference* in height between A and B.

Probably the picture is badly drawn, I suppose the difference in height between A and B is 50m [the units for height are missing, too].
 
borgwal said:
The *change* in kinetic energy plus the *change* in potential energy equals zero here: so you do need to use the height at B, or more precisely, what matters is the *difference* in height between A and B.

Probably the picture is badly drawn, I suppose the difference in height between A and B is 50m [the units for height are missing, too].

So i use the Diffrence in height of where it starts and where the point is?
 
Articulum said:
So i use the Diffrence in height of where it starts and where the point is?

Exactly!
 
Thank you so much made my Physics work much easier
 

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