Calculating Energy Transformed by Friction in a Falling Satellite

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To calculate the energy transformed by friction as a satellite falls, start by applying the work-energy principle: KE_initial + PE_initial = KE_final + PE_final + W_friction. The initial kinetic energy can be calculated using the formula 1/2mv^2, while the potential energy requires the gravitational formula GM1M2/r^2. To find the initial velocity, consider the satellite's orbital speed at 500 km altitude. The final kinetic energy is determined by the impact speed of 2.00 km/s. Understanding these equations will help in solving the problem effectively.
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A 500 kg satellite is in a orbit at an altitude of 500 km above the Earth's surface. because of the air friction, the satellite eventually falls to the Earth's surface, where it hits the ground with a speed of 2.00 km/s.how much energy was transformed into the internal energy by means of friction?
I really got no clue to solve this one. Could you guy give me some instructions? If you could, give me a lecture about this type of problem. Thank you
 
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This is a work-energy problem. Consider solving the equation:
KE_0+PE_0=KE_f+PE_f+W_{friction}
 
Take the initial energy (potential plus kinetic) and subtract the final energy.
 
for kinetic energy I will us 1/2mv^2 .How do I find the V initial , Also, for Potential energy , I have to use GM1M2/r2 ? is it right? Thank you
 
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