Calculating Energy Transported by an EM Wave with a 36.5 mV/m E Field

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To calculate the energy transported by an electromagnetic (EM) wave with an rms electric field strength of 36.5 mV/m across a 1.15 cm² area, the energy density formula u = ε₀E² is applied, yielding a value in J/m³. This energy density is then multiplied by the area to convert it to J/m. To find the total energy transported per hour, the speed of light is used to convert the power into J/h, factoring in the time duration of one hour. The calculations involve converting the speed of light from m/s to m/hr and multiplying by the total seconds in an hour. This method effectively determines the energy transported by the EM wave over the specified area and time.
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Homework Statement


How much energy is transported across a 1.15 cm2 area per hour by an EM wave whose E field has an rms strength of 36.5 mV/m?


Homework Equations


u (energy per unit volume) = \epsilon_0 E^2 \frac{J}{m^3}

The Attempt at a Solution


Since I have u = 8.85*10-12*(36.5*10-3)2 J/(m^3). I multiply this by the given area (1.15 cm2) which gave me units of J/m. The only other thing that seems to make any sense that would get me to J/h would be to multiply by the speed of light in meters per hour.
 
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Hi Queue, that sounds reasonable to me - multiplying by the speed of light gives the power crossing the surface area. Transferring the speed to m/hr is equivalent to finding the power transfer in J/s, using m/s, then multiplying by 3600s to find the total energy trasnferred in an hour
 
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