Calculating Final Velocity of 100kg Object Dropped from 100m

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SUMMARY

The final velocity of a 100kg object dropped from a height of 100m can be calculated using the principle of conservation of energy. The potential energy at height h is given by the formula mgh, where m is mass (100kg), g is the acceleration due to gravity (approximately 9.81 m/s²), and h is the height (100m). At ground level, all potential energy converts to kinetic energy, allowing the equation mgh = 0.5mv² to be used to solve for the final velocity (v). The final velocity is determined to be approximately 44.72 m/s.

PREREQUISITES
  • Understanding of gravitational potential energy
  • Familiarity with kinetic energy equations
  • Basic algebra for solving equations
  • Knowledge of the acceleration due to gravity (9.81 m/s²)
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  • Study the conservation of energy principles in physics
  • Learn about free fall motion and its equations
  • Explore the effects of air resistance on falling objects
  • Investigate the relationship between mass, weight, and gravitational force
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Physics students, educators, and anyone interested in understanding the dynamics of falling objects and energy conservation principles.

charlie hogg
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How can I calculate the impact speed(final velocity) of an object of mass 100kg, dropped from a height of 100m, only considering gravity.
 
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Pretty straight forward isn't it? Since you are only considering gravity, total energy is conserved. At height h, the object's potential energy, relative to the ground at height 0, is mgh. Since it is dropped, its velocity and so kinetic energy is 0. At the ground, height 0, its potential energy, relative to height 0, is 0 so all of that potential energy is converted to kinetic energy. Set the formula for kinetic energy equal to mgh and solve for v.
 
thanks
 

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