Calculating Flow Rate: Oil in a Pipe

Click For Summary
SUMMARY

The discussion focuses on calculating the flow rate of oil in a pipe under various conditions, specifically horizontal, inclined at 8 degrees, and declined at 8 degrees. Key parameters include a pressure of 135 kPa at 15m from the end, 88 kPa at discharge, a pipe diameter of 1.5 cm, oil density of 876 kg/m³, and dynamic viscosity of 0.24 kg/m·s. The Reynolds number (Re) is calculated using the formula Re=V*D*ρ/μ, indicating laminar flow when Re is 13.8, leading to the use of the Darcy friction factor f=64/Re. The user struggles with unit conversions and achieving a realistic value for f, which converges to an incorrect value of 12734.79.

PREREQUISITES
  • Understanding of fluid dynamics principles, specifically flow rate calculations.
  • Familiarity with the Reynolds number and its significance in flow classification.
  • Knowledge of the Darcy-Weisbach equation for head loss in pipes.
  • Proficiency in unit conversions relevant to pressure, density, and viscosity.
NEXT STEPS
  • Review the derivation and application of the Darcy-Weisbach equation for head loss.
  • Learn about the implications of laminar vs. turbulent flow in fluid mechanics.
  • Study the effects of pipe inclination on flow rate and pressure loss.
  • Explore advanced fluid dynamics simulations using software like ANSYS Fluent.
USEFUL FOR

Students in engineering disciplines, particularly those studying fluid mechanics, as well as professionals involved in pipeline design and analysis.

Vidatu
Messages
63
Reaction score
0

Homework Statement



Oil flowing through a pipe, measured to be 135kPa 15m from the end and 88kPa discharging from the end. The diameter of the pipe is 1.5cm, the density of the oil is 876kg/m^3, and the dynamic viscosity is 0.24kg/m*s.
Find flow rate for:
a) horizontal
b) inclined 8 degrees
c) declined 8 degrees

Homework Equations



Re=V*D*\rho / \mu
\Delta P = h_L * \rho *g
h_L = f*(L/D)*(V^2)/(2*g)
f=64/Re (laminar flow only)

where:
Re = Reynolds Number
rho = densityf=64/Re
mu = dynamic viscosity
delta P = pressure loss
h_L = head loss
L = length
D = diameter
f = Darcy friction coefficient

The Attempt at a Solution


I solved for Re in terms of V, and for V in terms of f, and then I guessed f=0.0150 for a starting point. I got an Re of 13.8, indicating laminar flow, so I used f=64/Re and iterated. However, my answer finally converged on f=12734.79 which doesn't look at all right. Am I doing something wrong?
 
Physics news on Phys.org


Probably unit related. The equation for delta_p(your second equation) will have units in pascal.
 


Vidatu said:

Homework Statement



Oil flowing through a pipe, measured to be 135kPa 15m from the end and 88kPa discharging from the end. The diameter of the pipe is 1.5cm, the density of the oil is 876kg/m^3, and the dynamic viscosity is 0.24kg/m*s.
Find flow rate for:
a) horizontal
b) inclined 8 degrees
c) declined 8 degrees

Homework Equations



Re=V*D*\rho / \mu
\Delta P = h_L * \rho *g
h_L = f*(L/D)*(V^2)/(2*g)
f=64/Re (laminar flow only)

where:
Re = Reynolds Number
rho = densityf=64/Re
mu = dynamic viscosity
delta P = pressure loss
h_L = head loss
L = length
D = diameter
f = Darcy friction coefficient

The Attempt at a Solution


I solved for Re in terms of V, and for V in terms of f, and then I guessed f=0.0150 for a starting point. I got an Re of 13.8, indicating laminar flow, so I used f=64/Re and iterated. However, my answer finally converged on f=12734.79 which doesn't look at all right. Am I doing something wrong?

You need to show your work so we can give you guidance.

CS
 

Similar threads

Replies
15
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
9
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
2
Views
6K
Replies
6
Views
6K
Replies
13
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
31
Views
4K