Flow & Viscosity: Estimate Max Temp of Crude Oil for 4Kg/s Flow

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Discussion Overview

The discussion revolves around estimating the maximum temperature of crude oil required to maintain laminar flow at a rate of 4 kg/s through a 0.3-meter diameter pipe. Participants explore the relationship between viscosity and temperature, using provided data to calculate relevant parameters.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant calculates the maximum temperature for laminar flow to be around 16°C based on viscosity data and Reynolds number.
  • Another participant confirms the calculation but notes that specific gravity is not necessary for the solution.
  • A new member questions the use of 855 kg/m³ as the density of crude oil, seeking clarification on why it is not presented as 0.855.
  • Participants discuss the source of the temperature estimate, with one asking for clarification on how the temperature was derived from the viscosity table.
  • A later reply explains that the temperature was obtained by calculating the Reynolds number at different viscosities and interpolating to find the temperature at which the Reynolds number exceeds 2100.

Areas of Agreement / Disagreement

Participants generally agree on the calculation method but there is some confusion regarding the use of specific gravity and the derivation of the maximum temperature. The discussion remains unresolved regarding the clarity of the temperature estimation process.

Contextual Notes

Some participants express uncertainty about the assumptions made in the calculations, particularly regarding the interpretation of viscosity data and the conditions for laminar flow.

Who May Find This Useful

Students and individuals interested in fluid dynamics, particularly those studying the effects of temperature on viscosity in liquid flow scenarios.

cjm181
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Homework Statement


[/B]
For many liquids the viscosity is strongly dependent on temperature. Use the table below to estimate the required maximum temperature of crude oil to flow at a rate of 4Kg s-1 through a 0.3 metre diameter pipe whilst maintaining a laminar flow.

In the table it has in the rows.

temp 0 20 50 100 200
Viscosity 16 7.5 4 2.5 1.5Crude Oil (sg = 0.885)
Viscosity (x10-3 Nsm-2)https://www.physicsforums.com/threads/mechanical-flow-rate.863262/#post-5418137

Homework Equations


A=PIr^2

V=m/(PA)

Viscosity=(Pvd)/Re

The Attempt at a Solution



Area of pipe = PIr^2=PI*0.15^2=0.07069m^2

V=m/(pA)
V=4/(855*0.07069)
V=0.066m/s

So for the pipe of diameter 0.3m, to achieve 4kg/s we need a fluid velocity of 0.066m/s. (sounds really slow?)

Then
Reynolds # = (density)(velocity)(pipe diameter) / (viscosity)

Viscosity=(density)(velocity)(pipe diameter) / (reynolds)

so if the flow is to be laminar, set reynolds no to 1999

Viscosity=(855)(0.066)(0.3) / (1999)

Viscosity=0.00849 or 8.49x10^-3Nsm

so max temp would be around 16deg C. Can anyone confirm?

Kr
Craig
 
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Confirmed. Btw, you don't need to know the specific gravity to solve this.
 
Thanks Ches

Can you show me how to do it without SG?

Kr
Craig
 
$$Re=\frac{\rho vD}{\mu}=\rho v \left(\frac{\pi D^2}{4}\right)\frac{4}{\pi D\mu}=\frac{4\dot{m}}{\pi D\mu}$$
 
hi, I'm a new member, I was just hoping someone could explain why 855 has been used in some equations and why it isn't 0.855. Thanks
 
DC83 said:
hi, I'm a new member, I was just hoping someone could explain why 855 has been used in some equations and why it isn't 0.855. Thanks
HI DC83. Welcome to Physics Forums.

0.855 is the specific gravity, which is the density relative to water. The density of water is 1000 kg/m^3. So the density of the oil is 855 kg/m^3.
 
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Hi
cjm181 said:
so max temp would be around 16deg C
I'm just wondering from the post 1 said
Where do we get that Temperature from ? Is that came from the table or something ? as I have not got a clue.
 
jaff90110 said:
Hi

I'm just wondering from the post 1 said
Where do we get that Temperature from ? Is that came from the table or something ? as I have not got a clue.
Can you please explain your question more precisely?
 
I'm sorry , that was my mistake,
From the post # 1 that said the max temperature is around 16 degree C.
I'm wondering that where did cjm181 get that temperature from?
 
  • #10
jaff90110 said:
I'm sorry , that was my mistake,
From the post # 1 that said the max temperature is around 16 degree C.
I'm wondering that where did cjm181 get that temperature from?
He calculated the Reynolds number at the different temperatures based on the viscosities in the table, and then interpolated to find the temperature at which the Reynolds number exceeds 2100. Use semi-log paper to plot the viscosity as a function of temperature. Please show your graph.
 

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