Calculating Flow Rates in Pipe Networks: Head Loss Equations

Click For Summary
SUMMARY

This discussion focuses on calculating flow rates in pipe networks, specifically at a Y junction where water flows out of a tap and splits into two paths. The head loss equation presented is Total head = entry loss + tap loss + pipe loss 1 + loss in connector + pipe loss 2 + energy at exit. It is confirmed that separate values of velocity (U) must be used before and after the junction due to changes in volumetric flow rate. Accurate calculations require determining the new velocity after the junction to apply in subsequent loss calculations.

PREREQUISITES
  • Understanding of fluid dynamics principles
  • Familiarity with head loss equations
  • Knowledge of flow rate measurements (e.g., gallons per minute)
  • Ability to calculate velocity changes in fluid systems
NEXT STEPS
  • Study the Darcy-Weisbach equation for head loss in pipes
  • Learn about control volume analysis in fluid mechanics
  • Research the impact of pipe diameter on flow rates and velocities
  • Explore computational fluid dynamics (CFD) tools for simulating pipe networks
USEFUL FOR

Engineers, fluid mechanics students, and professionals involved in hydraulic design or water distribution systems will benefit from this discussion.

theoriginalh
Messages
5
Reaction score
0
Hi. I'm trying to determine the flow rates of water in a pipe network. At a junction in a pipe, for example a simple y junction where the water heads out of a tap down a short length of tube before splitting into two lengths of tube of the same diameter, would the head loss equation for one of the outlets be.

Total head=entry loss+tap loss+pipe loss 1+loss in connector+pipe loss 2+energy at exit

I am pretty confident of this but wondered if I would need to take separate values of U for before and after the junction, in the U^2/2g terms on the right hand side of the equation (as the volumetric flow rate in the pipe changes). Any help would be appreciated.
 
Engineering news on Phys.org
Yes you will. Try taking a control volume around the Y. If you have 10 gpm coming in, you're going to have 10 gpm coming out, but in two separate paths. You will have to calculate the new velocity after the branch and use that in the loss calculations after that point (until it changes again that is).
 
I have encountered a vertically oriented hydraulic cylinder that is designed to actuate and slice heavy cabling into sections with a blade. The cylinder is quite small (around 1.5 inches in diameter) and has an equally small stroke. The cylinder is single acting (i.e. it is pressurized from the bottom, and vented to atmosphere with a spring return, roughly 200lbs of force on the spring). The system operates at roughly 2500 psi. Interestingly, the cylinder has a pin that passes through its...

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
6
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
13
Views
4K