Calculating Force in Lifting a 2.0kg Object

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To calculate the work done in lifting a 2.0kg object at a constant speed of 2.0 m/s for 5.0 seconds, the distance covered is determined to be 10 meters. Since the object is lifted at constant speed, the acceleration is zero, indicating that the net force acting on the object is also zero. The force applied by the person must equal the weight of the object, which is calculated using F=ma. Therefore, the work done can be calculated using the formula w=mgh, where h is the height lifted. This confirms that the correct approach to finding the work done is indeed using the gravitational potential energy formula.
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How much work is done by a person lifting a 2.0kg object from the bottom of a well at a constant speed of 2.0 m/s for 5.0s?

I know w=fd. I found the distance to be 10m. But what is the force? F=ma so what is the acceleration of the system?
 
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Since the object is being lifted at constant speed, what does that tell you about the acceleration? What's the net force on the object? (There are two forces acting on the object: the force applied by the person and the weight of the object.)
 
Wouldn't that mean that the acceleration is 0? So would I use w=mgh?
 
Yes and yes.
 

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