Calculating Force on Swimming Pool Bottom and Short Sides | Fluid Statics

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To calculate the force on the bottom of a swimming pool filled with water, the total weight of the water is determined to be 5.41E+06 N. For the force on each short side, the correct approach involves using the formula for pressure, P = F/A, where pressure is calculated based on the water's depth and density. The force on each side can be derived from the pressure at the midpoint of the water column multiplied by the area of the side. The user is struggling with applying the correct values in the formula, indicating a need for clarity on how to calculate pressure and force accurately. Understanding these principles is essential for solving fluid statics problems effectively.
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A swimming pool has dimension 23.0 m by 8.0 m with a depth of 3.0 m. When it is filled with water, what is the force (resulting from the water alone) on the bottom?

When it is filled with water, what is the force (resulting from the water alone) on each short side?

i figured out part a already by finding the weight of the water in the swimming pool and multiplying it by gravity (which gave me 5.41E+06 N) but i cannot figure out part b... am i suppose to use the formula
Pressure = F/A?? (i tried with serveral different numbers and still got the wrong answer)
 
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F=\rho g A d
 

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