Calculating Frequency of Electron Orbit in Hydrogen Atom

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To calculate the frequency of an electron orbiting a hydrogen atom, the attractive force of 8.18 × 10−8 N and the orbit radius of 4.57 × 10−11 m are used. The relevant equations include the centripetal force formula Fc = mv²/r and the circumference of the orbit, which is 2πr. The discussion raises a question about which mass to use in the calculations—whether the mass of the proton or the electron. Participants are working through the calculations to determine the frequency in revolutions per second. The focus remains on applying the correct physics principles to solve the problem accurately.
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Homework Statement


In a hydrogen atom, the electron in orbit
around the proton feels an attractive force of
about 8.18 × 10−8 N.
If the radius of the orbit is 4.57 × 10−11 m,
what is the frequency in revolutions per second?
Answer in units of rev/s.


Homework Equations


Fc= mv^2/r
(2 pi r)



The Attempt at a Solution


(8.18 x 10^-8) x (4.57 x 10^-11)/ which mass? proton or electron?
pi( 2 x 4.57 x 10^-11)
 
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