Calculating Friction Force to Stop a Rolling Ball

Click For Summary
SUMMARY

The discussion focuses on calculating the friction force necessary to stop a rolling ball on a cement floor. Participants emphasize the relationship between kinetic force and friction force, asserting that the magnitude of the kinetic force equals the friction force required for deceleration. The conversation highlights the importance of knowing the ball's weight and speed to accurately determine the friction force needed to halt its motion.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of friction coefficients
  • Familiarity with kinetic energy concepts
  • Ability to perform calculations involving force, mass, and acceleration
NEXT STEPS
  • Study the principles of Newton's second law of motion
  • Learn about the coefficient of friction for different surfaces
  • Explore kinetic energy and its relation to stopping distances
  • Investigate real-world applications of friction in sports and engineering
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding the dynamics of motion and friction in practical scenarios.

kristy_vincen
Messages
3
Reaction score
0
The question is BASICALLY: A ball is rolling on a cement floor (accelerating). Determine the friction force required to stop the ball.

Of course it gives you the weight and speed of the ball, and I believe i know the answer. I just want to check it.

If I figure out the magnitude of of kinetic force, would it not take the same amount of friction force to stop the ball? So the kinetic force = friction force?

Thank you
 
Physics news on Phys.org
welcome to pf!

hi kristy! welcome to pf! :smile:
kristy_vincen said:
The question is BASICALLY: A ball is rolling on a cement floor (accelerating). Determine the friction force required to stop the ball.

Of course it gives you the weight and speed of the ball …

uh-uh :redface: … please tell us the exact question
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
14
Views
3K
  • · Replies 32 ·
2
Replies
32
Views
3K
Replies
24
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
43
Views
4K
Replies
61
Views
3K
  • · Replies 42 ·
2
Replies
42
Views
3K