Calculating Gas Temperature Change Using the Ideal Gas Law

[turnip]

Homework Statement

A gas at 293.15 degrees kelvin and atmospheric pressure is compressed to a volume one fifteenth as large as its original volume and absolute pressure of 3000kPa. What is the new temperature of the gas?

Homework Equations

p1v1/t1=p2v2/t2

The Attempt at a Solution

if i rearrange the equation above for t2 i get t2=101/293.15 x 3000 x 1/15= 1.722x10-3

if i do it the wrong way and flip the divisions around so that t2=293.15 x 3000 x 1/15/101 =580.49

i take the 580 - 273 =307

307 is the right answer. perhaps i am doing it the right way, i just don't understand how this could be correct
please explain this to me

 

[saket]

if i rearrange the equation above for t2 i get t2=101/293.15 x 3000 x 1/15= 1.722x10-3

u r getting it 1/t2 and not t2.. verify urself.

 

[turnip]

haha can't believe i didnt get that
i need more sleep :P

 

[turnip]

oh and thanks :)