Calculating Gravitational Potential

AI Thread Summary
The discussion revolves around calculating gravitational potential as one moves closer to Earth, specifically from 3800 km to 2250 km above the surface. The participant calculated gravitational potentials at both points and found that moving closer results in a decrease in gravitational potential, contrary to the textbook's example. The confusion arises from the textbook's definition of "gain," which seems to refer to the absolute value of the change rather than a straightforward increase or decrease. It is suggested that clarification from an instructor regarding the term "gain" would be beneficial for exam purposes. Understanding the distinction in definitions is crucial for accurate calculations in gravitational potential scenarios.
Jimmy87
Messages
692
Reaction score
19

Homework Statement


I was going through a worked example in my textbook to gain a better understanding but after I had a go myself it is the opposite to what I have calculated. I have attached the worked example which asks you to calculate the gain in gravitational potential moving from a point that is 3800km away from the Earth's surface to a point that is 2250km away.

Homework Equations


V = - GM/R (where V is gravitational potential) using G as 6.67 x 10^-11 and M as 5.97 x 10^24 kg

The Attempt at a Solution


I thought as you move further away the gravitational potential increases as it is inversely proportional to the negative of 'R'. So how can moving closer to the Earth be a GAIN in gravitational potential. When I calculated it I added the radius of the Earth to the distances from the Earth. I don't see how yo can leave that out like they do in the worked solution? So I did:

Potential at A = -GM/R = - 3.92 x 10^7 J/kg
Potential at B = -GM/R = - 4.62 x 10^7 J/kg

I used the radius of the Earth as 6.371 x 10^6 m

So I thought any change in physics is always the final minus the inital. So if we are going from point A to point B it would be:

change in gravitational potential = -4.62 x 10^7 - (-3.92 x 10^7) = -0.7 x 10^7 J/kg

I thought this made sense to me as I thought gravitational potential energy and gravitational potential always increase as you move away from the gravitating object. Since B is closer to the Earth I expected my answer to be negative meaning the gravitational potential has decreased as you have got closer to the gravitating object - which is has! However, the worked example is the complete opposite to what I have done so now I am confused. Please help!
 

Attachments

Physics news on Phys.org
You are correct and I agree that the example is confusing. The gravitational potential decreases as one moves nearer the center of the Earth. It seems that this textbook has defined "gain" as the absolute value of "change", the latter always being final minus initial value.

On Edit: The question would make more sense if it asked, "What is the gain of gravitational potential between the two points?"
 
  • Like
Likes Jimmy87
kuruman said:
You are correct and I agree that the example is confusing. The gravitational potential decreases as one moves nearer the center of the Earth. It seems that this textbook has defined "gain" as the absolute value of "change", the latter always being final minus initial value.

On Edit: The question would make more sense if it asked, "What is the gain of gravitational potential between the two points?"

Thanks. Would I get it right in an exam though? As my answer and the textbook answer are completely different.
 
Jimmy87 said:
Thanks. Would I get it right in an exam though? As my answer and the textbook answer are completely different.
Since your instructor will be grading your exam, I think you should get a clarification of what "gain" means from him/her. Then you will be sure to get it right.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top