Calculating 'half-life' *help : /

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To calculate the half-life of a radioactive isotope, the decay rate decreases from 8305 to 3070 decays per minute over 5 days. The relevant equation is N = N0 e^(-lambda*t), where lambda is the decay constant. By using the formula ln(R1/R2) = lambda * delta t, the decay constant lambda is determined to be approximately 0.199. Subsequently, the half-life T1/2 is calculated using T1/2 = ln(2)/lambda, resulting in a half-life of about 3.48 days. This process illustrates the steps needed to solve half-life problems effectively.
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Hello :)

I came across a question and I haven't been able to solve it so far. It would be great if maybe someone could give me a few tips.

Here is the question:

Measurements of the radioactivity of a certain isotope tell you that the decay rate
decreases from 8305 decays per minute to 3070 decays per minute over a period of 5.00
days.

What is the half-life T1/2 of this isotope?

How can I get the right answer for this question? I never really worked with those half-life
questions. I am still interested how it works.

thanks :)
 
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Hi MrChaos and welcome to PF. Please observe our rules and use the template for posting requests for help with homework.

What equation do you know that relates activity to time and half-life>
 
umm...

N = N0 e-lambda*t

i'm not sure if this ones right

T1/2= ln 2/lambda
 
mission impossible now complete
on my last attempt i got it right

ln (R_1/R_2)= lambda*deltat
ln (8305/3070)= lambda*5days
0.995180181= lambda*5days
0.995180181*1/5 = 0.19903636 = lambda

lambda*T= ln 2= 0.6931
0.6931/0.19903636= T
T_1/2= 3.482283978
= 3.48 days

:)
 
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