Calculating Heat of Object in Re-Entry: Kelvin °

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Discussion Overview

The discussion revolves around the calculation or estimation of heat experienced by an object during atmospheric re-entry, specifically in Kelvin. Participants explore the factors influencing this heat, such as velocity, mass, and the nature of the heating process, including the roles of compression and friction.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions the terminology of "re-entry," suggesting that it applies only to objects sent from Earth, while meteors are simply entering the atmosphere.
  • Another participant proposes that the heat experienced by an object is primarily due to compression rather than friction, speculating that frictional heating may be countered by rapid cooling from the air.
  • A later reply mentions that the temperature of the air can be determined if the pressure in front of the object is known, introducing the concept of stagnation temperature.
  • One participant suggests using the color of a meteor trail to estimate temperature, referencing blackbody radiation and Wien's law, estimating around 5000K for meteor trails and 2000K for Space Shuttle materials during re-entry.
  • Another participant provides a link to NASA's brief on stagnation temperature, noting that the graph presents temperatures in degrees Rankine and discusses the implications of imperfect gases on stagnation temperature calculations.

Areas of Agreement / Disagreement

Participants express differing views on the primary sources of heat during re-entry, with some emphasizing compression and others considering friction. The discussion remains unresolved regarding the exact processes and calculations involved.

Contextual Notes

Participants acknowledge limitations in their knowledge and the need for corrections from more knowledgeable individuals. There are references to specific formulas and concepts, but no consensus on their application or accuracy is reached.

nicholas0211510
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How do scientists calculate or estimate the heat of a object in atmospheric re-entry in ° kelvin (the specific formula or formulas if any exist). I'm guessing it has to do with velocity and mass of the object but I'm not sure on the whole process

Thanks in advanced :)
 
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I don't have an answer to your question, but just FYI "reentry" is a term only used for stuff that we sent up and are getting back (whether we like it or not). Meteors have never been here so they are not RE-entering, just entering. Also, I think the heat you are talking about is just what exists at the surface of the object entering the atmosphere. For example, the Space Shuttle ablative tiles got REALLY hot, but the rest of the vehicle didn't. So "meteor heat" isn't quite the right concept, it's more "surface heat of object entering atmosphere".

phinds the NitPicker :smile:
 
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Thanks for some clarification :)
 
Disclaimer: I may not know what I'm talking about. I would appreciate it if someone more knowledgeable than I could correct any errors.

I recall reading somewhere, I have no idea where, that the majority of heat comes from, compression, rather than friction. I would imagine that the heating from friction would pretty well cancel out with how quickly the air would cool it.

If that is correct, you should be able to determine the temperature of the air if you can calculate the pressure in front of the object.
 
nicholas0211510 said:
How do scientists calculate or estimate the heat of a object in atmospheric re-entry in ° kelvin (the specific formula or formulas if any exist). I'm guessing it has to do with velocity and mass of the object but I'm not sure on the whole process

Thanks in advanced :)

You can get a rough estimate by the color of the meteor trail (assuming blackbody radiation and using Wien's law)- by my eye, the color is orange-red, corresponding to about 5000K. The space shuttle materials, during re-entry, had to deal with about 2000K loads
 
Murdock said:
Disclaimer: I may not know what I'm talking about. I would appreciate it if someone more knowledgeable than I could correct any errors.

I recall reading somewhere, I have no idea where, that the majority of heat comes from, compression, rather than friction. I would imagine that the heating from friction would pretty well cancel out with how quickly the air would cool it.

If that is correct, you should be able to determine the temperature of the air if you can calculate the pressure in front of the object.
Stagnation temperature.
Nasa has a brief on it.
http://www.grc.nasa.gov/WWW/BGH/stagtmp.html

The graph gives temperature in degrees Rankine.

The dotted lines for an imperfect gas means that the object( or the air) has to be traveling faster to give the same stagnation temperature, or, at the same Mach number the imperfect gas will give a lower stagnation temperature.

Of course that temperature is only at one small spot where the air and the object are at the same velocity relative to one other, hense the term stagnation.
 

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