- #1
reese houseknecht
- 26
- 1
Ok, so I am am trying to make a homemade capacitor that is 4700pf and 15kv. polyester at 125 micrometers thick can withstand 15kv so were good. here is the equation i used
C=ε0 K A / D
Where C = capacitance, ε0 is epsilons constant, K = dielectric constant, A = area of aluminum foil, and D is the space between the 2 conductors (the thickness of my dielectric)
so here is my values
4.7x10-9F = 8.85x10-12 * 4.7 * A / 0.000127M
Farads Epsilon Dielectric Area Meters
i got 0.0142 for A after solving. this is about 3" of area? i don't get it, that is way to small! BTW these capacitors arent being rolled up, they are low inductance so its just flat
C=ε0 K A / D
Where C = capacitance, ε0 is epsilons constant, K = dielectric constant, A = area of aluminum foil, and D is the space between the 2 conductors (the thickness of my dielectric)
so here is my values
4.7x10-9F = 8.85x10-12 * 4.7 * A / 0.000127M
Farads Epsilon Dielectric Area Meters
i got 0.0142 for A after solving. this is about 3" of area? i don't get it, that is way to small! BTW these capacitors arent being rolled up, they are low inductance so its just flat