Calculating Inductance for 5kV Flyback Converter in 1mS

hobbs125
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I am wondering, In a flyback inductor used for a boost converter, what inductance would be required to produce 5kV across the flyback inductor in 1mS with a current of 10mA?


I know the formula would probably be V=L di/dt but I'm not sure how to rearrange it to get the correct answer.
 
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hobbs125 said:
I am wondering, In a flyback inductor used for a boost converter, what inductance would be required to produce 5kV across the flyback inductor in 1mS with a current of 10mA?I know the formula would probably be V=L di/dt but I'm not sure how to rearrange it to get the correct answer.
di/dt is simply the rate of change of current which you defined as 10A/sec. Solve for the inductance L in Henries.

Please exercise caution if this is other than an academic exercise. And, aside from the obvious safety hazards, building high voltage inductors requires other expertise - special insulating materials, placement, etc.
 
H=V.s/A refer this
http://en.wikipedia.org/wiki/Henry_(unit )
 
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The Flyback boost voltage doesn't really depend on the primary inductance.

The primary inductance together with the peak current defines the amount of energy (not voltage) that the coil can transfer on each cycle.

When the main switch opens, you can treat that as instantaneous. L di/dt can be huge. In a real Flyback, you allow the secondary voltage to go up to some particular voltage by connecting the secondary to a capacitor.

If for some insane reason you want the secondary voltage to go really high, you have to take steps to make sure that voltage isn't transformed back to the primary side where it will probably destroy the switch.
 

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