Calculating Initial Speed and Velocity of Thrown Keys

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The problem involves a man throwing keys vertically upward to his wife, who catches them 4.0 m above after 1.5 seconds. The initial speed of the keys was calculated to be 10.016 m/s, using the equation of motion. The final velocity of the keys just before being caught was determined to be -4.684 m/s, indicating downward motion. The calculations were confirmed as correct by another participant in the discussion. The trajectory of the keys can be represented in a diagram, illustrating their upward and downward motion.
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Homework Statement



A man standing on the sidewalk throws a set of keys vertically upward to his
wife in the window of their apartment 4.0 m above. The wife catches the keys
1.5 s later. (a) With what initial speed were the keys thrown? (b) What is the
velocity of the keys just before they were caught? (c) Draw a diagram showing
the trajectory of the keys.



The Attempt at a Solution




d= 4.0 m
Δt= 1.5 s
g= -9.8 m/s^2

Δd= ViΔt+1/2aΔt

-ViΔt= 1/2 at2-Δd

-Vi= 1/2 at2- Δd /Δt

-Vi= -10.016 m/s

ANSWER FOR A ->>Vi= 10.016 m/s

b) Vf= Vi+at

Vf= (110.016 m/s)-(9.8)(1.5)= (-4.684m/s)

ANSWER FOR B >> -4.684 m/s
 
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Hi cbrowne,

cbrowne said:

Homework Statement



A man standing on the sidewalk throws a set of keys vertically upward to his
wife in the window of their apartment 4.0 m above. The wife catches the keys
1.5 s later. (a) With what initial speed were the keys thrown? (b) What is the
velocity of the keys just before they were caught? (c) Draw a diagram showing
the trajectory of the keys.



The Attempt at a Solution




d= 4.0 m
Δt= 1.5 s
g= -9.8 m/s^2

Δd= ViΔt+1/2aΔt

-ViΔt= 1/2 at2-Δd

-Vi= 1/2 at2- Δd /Δt

-Vi= -10.016 m/s

ANSWER FOR A ->>Vi= 10.016 m/s

b) Vf= Vi+at

Vf= (110.016 m/s)-(9.8)(1.5)= (-4.684m/s)

ANSWER FOR B >> -4.684 m/s


Your answers look right to me.
 
Your answers are correct.
 
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