Calculating K Value for Fischer Esterification Homework

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SUMMARY

The discussion centers on calculating the equilibrium constant (K) for Fischer esterification, specifically with a value of K=2, which yields approximately 59% of the theoretical yield for a 1:1 ratio of reagents. The equilibrium expression is defined as K = [ester][H2O] / [acid][alcohol]. Participants emphasize that this K value is likely derived from experimental data rather than theoretical calculations, suggesting that the theoretical yield should incorporate the known K value for accurate predictions.

PREREQUISITES
  • Understanding of chemical equilibrium concepts
  • Familiarity with Fischer esterification reactions
  • Knowledge of equilibrium constant calculations
  • Basic skills in interpreting chemical equations
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  • Research the derivation of equilibrium constants in chemical reactions
  • Study the impact of K values on reaction yields in Fischer esterification
  • Explore experimental methods for determining K values
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Chemistry students, laboratory researchers, and educators involved in organic chemistry and reaction kinetics will benefit from this discussion.

epyfathom
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Homework Statement


Hi.

In I'm doing a proposal for a lab and in it, it says that with an equilibrium constant value of 2 (K=2), the best yield would be about 59% of theoretical for a 1:1 ratio of reagents. I'm guessing it has to do with this equation, but I'm still sure how they calculated this value.

K = [ester][H2O] / [acid][alcohol]


Please show me how they got this value..


Thank you.
 
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I think it is an experimental value, it doesn't fit results of obvious approaches. Besides, I would say theoretical yield should take K (if known) into account.

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