Calculating Length of Airplane Start Lane for 300 km/h Acceleration

  • Thread starter Thread starter Izekid
  • Start date Start date
  • Tags Tags
    Airplane
AI Thread Summary
To calculate the length of an airplane's start lane for a constant acceleration of 1.6 m/s² to reach 300 km/h (83.3 m/s), the correct time must be determined first. The initial velocity is 0 m/s, and the time to reach the final velocity is calculated incorrectly as 132.8 seconds; it should be much shorter. The correct time is found by dividing the final velocity by acceleration, which results in a time of approximately 52.08 seconds. Using this time in the equation for distance, S = 1/2(v0 + v)t, leads to a much shorter start lane length. The final calculation reveals that the start lane should be approximately 2,166 meters long.
Izekid
Messages
40
Reaction score
0
I have a hard one here :
The lane for starting a airplane must be long enough for a airplane to accelerate to 300km/h with a constant acceleration on 1.6m/s2. How long must the startlane be?

This is what I've found out,

I take 300km/h and make it to m/s
300 / 3.6 = 83,3m/s
Then I because I don't know the time I take
t=v/a 83,3/1,6=132,8sek
Then I take
S=1/2(v0+v)*t = 1/2(0+83)*132,8 = 5511m = 5,5km

But I think that's not the right answer what have I done wrong?

Thankful for all help
 
Physics news on Phys.org
There is a solution to this problem. Basic constant acceleration equations are your best friend here.

You were right to convert your final velocity to m/s. You also have an initial velocity which is not stated, but you can say that initial velocity is 0.

You made a mistake with your time calculation. (83.3)/(1.6) can not be 132 sec. You are dividing by a number bigger than 1. The number must be smaller than 83.3. There's the hint for you. Your last step was correct but using the wrong time number.
 
thx... small stupid misstakes
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top