Calculating Linear Expansion with Specific Heat Capacity and Mass Density?

AI Thread Summary
The discussion revolves around calculating linear expansion using specific heat capacity and mass density. The initial attempt at a solution was incorrect, prompting a request for assistance. There is uncertainty regarding whether the heat capacity value of 390 J/K should be interpreted as specific heat capacity of 390 J/(kg K). Clarification on this point could help in utilizing the provided mass density effectively. Accurate interpretation of these values is crucial for solving the problem correctly.
Kara4566
Messages
4
Reaction score
0
Homework Statement
A 1.0m long rod of metal has a diameter of 0.75cm. This metal has
a coefficient of linear expansion α = 4.8 × 10−5 1/K, a density of 9.7 ×10^3 kg/m^3, and heat capacity of 390 J/K.
How much energy needs to be added as heat to increase the length of the rod by 7.5 × 10−3m?
Relevant Equations
change in Length= (Initial Length)(Coefficient of linear expansion)(change in temperature)
242182


Above is my attempt at a solution, however, this did not yield the correct answer. Any help is greatly appreciated!
 
Physics news on Phys.org
I wonder if the heat capacity of 390 J/K is really meant to be a specific heat capacity of 390 J/(kg K). Then, you can make use of the mass density given in the problem.
 
  • Like
Likes Kara4566
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
2
Views
237
Replies
13
Views
2K
Replies
6
Views
2K
Replies
3
Views
2K
Replies
4
Views
2K
Replies
2
Views
3K
Replies
4
Views
9K
Back
Top