Calculating Magnetic Flux in a Bent Square Loop with a Uniform Magnetic Field

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SUMMARY

The discussion focuses on calculating the magnetic flux through a bent square loop measuring 13.5 cm by 13.5 cm in a uniform magnetic field of 0.463 T directed at an angle of 33°. The formula used for magnetic flux is MF = AB cos θ, where A represents the area of the loop and θ is the angle between the magnetic field and the normal to the surface. The correct calculation involves using the area of the square loop and the cosine of the angle to determine the magnetic flux accurately.

PREREQUISITES
  • Understanding of magnetic flux concepts
  • Familiarity with the formula MF = AB cos θ
  • Basic knowledge of geometry related to area calculation
  • Ability to perform trigonometric calculations
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  • Study the application of trigonometry in physics problems
  • Explore examples of magnetic flux calculations in different geometries
  • Learn about the implications of magnetic flux in electromagnetic theory
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Students studying physics, particularly those focusing on electromagnetism, as well as educators seeking to explain magnetic flux calculations in practical scenarios.

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Magnetic flux...PLEASE HELP!

Homework Statement


A 13.5 cm × 13.5 cm square bent at a angle 90°. A uniform 0.463 T magnetic field points downward at θ=33° angle. What is the magnetic flux through the loop? (a=6.75 cm, b=13.5 cm, c=6.75 cm.)

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Homework Equations





The Attempt at a Solution


MF = AB cos theta
Would it just be (.135 * .135) * 0.463 cos 33
I am not sure which area and angle to use?
 
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nevermind got it
 

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