Calculating Mass of a Vibrating String Using Known Quantities

AI Thread Summary
To calculate the mass of a vibrating string in the second harmonic, known quantities include amplitude (A), maximum velocity (v), string length (L), and tension (T). The wave speed can be determined using the relationship between maximum velocity and amplitude, where the maximum velocity is equal to Aω. By rearranging this relationship, one can solve for the angular frequency (ω) using the given maximum velocity. With ω known, the wave speed can be calculated, which can then be used to find the mass of the string. This approach effectively utilizes the properties of standing waves fixed at both ends.
zengodspeed
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Homework Statement


A second harmonic standing wave has the known quantities of Amplitude (max y at antinode) A, maximum velocity (y=0 at antinode) v, string length L, tension in the string T.

Given that we know that it is second harmonic, we can assume that λ = L

How can one determine the mass of the string?

Homework Equations



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The Attempt at a Solution



Attempt at solution:

Using the equation to solve for velocity:

I know that I can find the mass of the object if I can find the wave speed, but without knowing the frequency/period of the wave I do not see how I can find this.

Thanks in advance
 

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zengodspeed said:

Homework Statement


A second harmonic standing wave has the known quantities of Amplitude (max y at antinode) A, maximum velocity (y=0 at antinode) v, string length L, tension in the string T.

Given that we know that it is second harmonic, we can assume that λ = L

How can one determine the mass of the string?

Homework Equations



View attachment 215526

View attachment 215527

View attachment 215528

The Attempt at a Solution



Attempt at solution:

Using the equation to solve for velocity:

I know that I can find the mass of the object if I can find the wave speed, but without knowing the frequency/period of the wave I do not see how I can find this.

Thanks in advance
You havn't mentioned that either string is fixed at both end or fixed at one end
because normal frequencies of standing wave depend on how end is fixed
 
Abhishek kumar said:
You havn't mentioned that either string is fixed at both end or fixed at one end
because normal frequencies of standing wave depend on how end is fixed

Hi, sorry about that. The string is fixed at both ends.
 
zengodspeed said:
the frequency/period of the wave I do not see how I can find this.
Look at your third relevant equation. What does it say about the max vy?
 
haruspex said:
Look at your third relevant equation. What does it say about the max vy?

That the max vy is equal to the derivative of the second equation when y=0?
 
zengodspeed said:
That the max vy is equal to the derivative of the second equation when y=0?
Just fix on the third equation. As t and x vary, what is the max value of the right hand side?
 
haruspex said:
Just fix on the third equation. As t and x vary, what is the max value of the right hand side?

The maximum value of the right hand side would be Aω if x and t were chosen so that sin(kx) and cos(ωt) were both equal to 1.
 
zengodspeed said:
The maximum value of the right hand side would be Aω if x and t were chosen so that sin(kx) and cos(ωt) were both equal to 1.
Right, so what is the max value of vy?
 
The max value is equal to Aω. Therefore you can solve for ω by taking the ratio of the vy,max and the amplitude.
 
  • #10
zengodspeed said:
The max value is equal to Aω. Therefore you can solve for ω by taking the ratio of the vy,max and the amplitude.
Right, and you are given vy,max.
 
  • #11
haruspex said:
Right, and you are given vy,max.

Brilliant, thank you very much!
 
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