Calculating Mass % of H2CO3 from Reaction Equation

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Discussion Overview

The discussion revolves around calculating the mass percentage of H2CO3 in a reaction involving CaCO3 and H2SO4. Participants explore the interpretation of the problem statement and the necessary data for the calculation, including the mass of CaSO4 and the total mass of products.

Discussion Character

  • Homework-related
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant presents a reaction equation and attempts to calculate the mass percentage of H2CO3 based on the products formed.
  • Another participant interprets the mass percentage of H2CO3 as the ratio of its mass to the total mass of the products, suggesting the need for the mass of CaSO4.
  • There is a request for clarification on the exact statement of the problem to ensure proper understanding.
  • Assuming the mass of CaSO4 is 136 g, participants discuss how to calculate the ratio of H2CO3 to the total mass of products.
  • Concerns are raised about the completeness and correctness of the problem paraphrasing, with one participant suggesting that important details may have been overlooked.
  • Participants express differing interpretations of the original computation, with one noting it was the percentage of CO2 rather than H2CO3.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct interpretation of the problem statement or the necessary calculations. Multiple interpretations and uncertainties remain regarding the mass percentages involved.

Contextual Notes

There are unresolved assumptions about the problem statement and the completeness of the provided data, particularly regarding the total mass of products and the mass of H2CO3.

mmmeraki
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Hi! I got a question. I have been given the reaction of the equation and no other data. I have to calculate the mass percentage of H2CO3. The gas dissolves in water.

1. Homework Statement
CaCO3 + H2SO4 = CaSO4 + H2O(l) + CO2(g)

Homework Equations

The Attempt at a Solution


CaCO3 + H2SO4 = CaSO4 + H2O(l) + CO2(g)
1 mol 1 mol 1 mol 1 mol 1 mol
m (CO2) = 1 mol * 44g/mol = 44 g
m (H2O) = 1 mol * 18g/mol = 18 g
m (solution) = 44 g + 18 g = 62 g
% = (44 g / 66 g) * 100 = 70,96%
or
CaCO3 + H2SO4 = CaSO4 + H2O(l) + CO2(g)
n (CO2) = 1 dm3 / 22,4 dm3/mol = 0,045 mol
m (CO2) = 0,045 mol * 44 g/mol = 1,98 g
n (H2O) = 0,045 mol (1:1)
m (H2O) = 0,045 mol * 18 g/mol = 0,81 g
m (solution) 1,98 g + 0,81 g = 2,79 g
% = (1,98 g / 2,79 g) * 100 = 70,96%

Does it even make sense?
 
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I would interpret "the mass percentage of the H2CO3" as: the ratio of the mass of the H2CO3 over the total mass of the products, expressed as a percentage.

If that's what you want, then you will need to know the mass of one mol of CaSO4.
 
What is the exact statement of your problem?
 
.Scott said:
I would interpret "the mass percentage of the H2CO3" as: the ratio of the mass of the H2CO3 over the total mass of the products, expressed as a percentage.

If that's what you want, then you will need to know the mass of one mol of CaSO4.
Assume that it's 136 g. How do I calculate the ratio?
 
mmmeraki said:
Assume that it's 136 g. How do I calculate the ratio?
The mass of the H2CO3 (62) over the total mass of the products (__ + __).

But Chestermiller has a point. I am not convinced you have paraphrased the problem correctly and completely.
 
.Scott said:
The mass of the H2CO3 (62) over the total mass of the products (__ + __).

But Chestermiller has a point. I am not convinced you have paraphrased the problem correctly and completely.
It's possible that I forgot something. It was on the test.
 
mmmeraki said:
It's possible that I forgot something. It was on the test.
Your original computation was the percentage of mass of the CO2 in the solution to the solution (H2CO3).
I interpreted what you reported as the percentage of mass of the solution (H2CO3) to the total mass of the product (CaSO4+H2CO3).
 
.Scott said:
Your original computation was the percentage of mass of the CO2 in the solution to the solution (H2CO3).
I interpreted what you reported as the percentage of mass of the solution (H2CO3) to the total mass of the product (CaSO4+H2CO3).

Thanks! Now I got it. :)
 

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