Calculating Mass to Support Car Weight on Hydraulic Lift

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Homework Help Overview

The problem involves a hydraulic lift system with two pistons of different cross-sectional areas, where the goal is to determine the mass required on the smaller piston to support a car's weight. The context includes considerations of fluid density and the relationship between the areas of the pistons.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the forces on the pistons and the areas, with one participant attempting to apply a formula involving the gravitational force and area ratio. Others question the validity of the approach and suggest reconsidering the calculations.

Discussion Status

The discussion is ongoing, with some participants providing insights into the nature of hydraulic systems and the importance of area ratios. There is no explicit consensus on the approach to take, and participants are exploring different interpretations of the problem.

Contextual Notes

There is a mention of the oil density, with one participant questioning its relevance to the problem. Additionally, a participant indicates they have made further progress on a related question, suggesting that the problem may have multiple facets to consider.

mujadeo
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Homework Statement



A hydraulic lift has two connected pistons with cross-sectional areas 5 cm^2 and 550 cm^2. It is filled with oil of density 520 kg/m3.


a) What mass must be placed on the small piston to support a car of mass 1500 kg at equal fluid levels?



Homework Equations


Is the oil density a red herring in this question?


The Attempt at a Solution



F = mg (A1/A2)

F = mg (5cm/550cm)^2

F = (1500kg)(9.81)(5cm/550cm)^2

F = 1.261N = wrong!

please help!
 
Physics news on Phys.org
A hydraulic system is just ratios.
In this case just the ratio of the two areas
 
> F = (1500kg)(9.81)(5cm/550cm)^2


??
Re-think...
 

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