Calculating Micrometer Reading Change for 50 Fringes at λ = 550 nm

AI Thread Summary
The discussion centers on calculating the change in micrometer reading when 50 fringes pass, given a spectrometer calibration constant of 0.5 and a wavelength of 550 nm. The relevant equations include delta(l) = delta(n) * lambda / 2 and delta(m) = delta(l) / K. The attempted solution suggests that delta(l) equals 13,750 nm, leading to a micrometer reading change of 27,500 nm. One participant mentions familiarity with the problem, indicating it may be sourced from "Modern Physics for Engineers." The conversation highlights the application of physics equations to solve practical measurement issues in optics.
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Homework Statement




Suppose the calibration constant of your spectrometer is 0.5, and suppose the wavelength of the light is λ = 550 nm. How much does the micrometer reading change during the movement of M2 that generates the passage of 50 fringes?

Homework Equations



possibly delta(l)= delta(n)*lambda /2
delta(m)= delta(l)/K , K being some constant to find the distance

The Attempt at a Solution



possibly delta(l)=50* 550 nm/ 2 delta(m)= delta(l)/K = 13750 nm/(.5) =27500 nm
 
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Benzoate said:

Homework Statement




Suppose the calibration constant of your spectrometer is 0.5, and suppose the wavelength of the light is λ = 550 nm. How much does the micrometer reading change during the movement of M2 that generates the passage of 50 fringes?

Homework Equations



possibly delta(l)= delta(n)*lambda /2
delta(m)= delta(l)/K , K being some constant to find the distance

The Attempt at a Solution



possibly delta(l)=50* 550 nm/ 2 delta(m)= delta(l)/K = 13750 nm/(.5) =27500 nm

Is this from Modern Physics for Engineers? I have seen this problem before. When I get home in about an hour or two I'll try to digg up the answer.
 
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