Calculating minimum velocity around a loop

AI Thread Summary
To determine the minimum velocity required for an object to complete a loop while counteracting gravity, it is essential to analyze the forces acting on the object at the top of the loop. At this point, the gravitational force must equal the centripetal force needed to keep the object in circular motion, which implies that one force will be zero. The centripetal acceleration can be calculated using the object's velocity and the radius of the loop. The discussion emphasizes that the acceleration at the top of the loop must remain non-negative to ensure the object does not fall off. Understanding these principles is crucial for solving the problem effectively.
Nouo
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So I had this question for physics about something going around a loop. The question asked what the minimum velocity to counteract gravity is if something is going around a loop. hint: One force will be zero.

I'm not sure how to figure this out, can someone help?
 
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Can you calculate the centripetal acceleration of a particle moving at some velocity around the loop? You can assume the loop is of radius r and treat it as a constant.
 
If an object is going around a loop of radius R at constant angular velocity, \omega then its position vector (taking center of the loop to be (0, 0) and the objects position at t= 0 to be (1, 0)) is R cos(\omega t)\vec{i}+ R sin(\omega t)\vec{j}. Its velocity vector will be -\omega R sin(\omega t)\vec{i}+ \omega R cos(\omega t)\vec{j} and its acceleration vector will be -\omega^2 R cos(\omega t)\vec{i}- \omega^2 R sin(\omega t)\vec{j}. In order to stay on the loop, the acceleration at the top (\theta= \pi/4) must be non-negative.
 
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