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Calculating Molal Boiling point elevation constant! HELP!
So here's how I did my problem, but the answer I arrived with is wrong. I need help with this...
Carbon disulfide (CS2) boils at 46.30°C and has a density of 1.261g/mL.
When 0.250 mol of a nondissociating solute is dissolved in 400.0 mL of CS2, the solution boils at 47.46°C. What is the molal boiling point elevation constant for CS2?
Normal Boiling Point: 46.3°C
0.250mol of solute
400.0mL of CS2 (solvent)
ΔT_{b}=k_{b}(molality)
ΔT_{b}=47.46-46.30=1.16°C
molality = 0.250mol/0.400kg = 0.625m
k_{b}= ΔT_{b}/molality.
k_{b}=1.16°C/0.625=1.856.
So here's how I did my problem, but the answer I arrived with is wrong. I need help with this...

Carbon disulfide (CS2) boils at 46.30°C and has a density of 1.261g/mL.
When 0.250 mol of a nondissociating solute is dissolved in 400.0 mL of CS2, the solution boils at 47.46°C. What is the molal boiling point elevation constant for CS2?
Homework Statement
Normal Boiling Point: 46.3°C
0.250mol of solute
400.0mL of CS2 (solvent)
Homework Equations
ΔT_{b}=k_{b}(molality)
The Attempt at a Solution
ΔT_{b}=47.46-46.30=1.16°C
molality = 0.250mol/0.400kg = 0.625m
k_{b}= ΔT_{b}/molality.
k_{b}=1.16°C/0.625=1.856.
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