- #1
assaftolko
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Homework Statement
We have the buffer Tricine 0.1M and pKa=8.15 and the pH=8.8
Homework Equations
what are the molar conc. of tricine+ (the protonated form of tricine) and tricine0 (the deprotonated form of tricine)?
The Attempt at a Solution
Well, if you go to henderson-hassalbach equation you get:
8.8=8.15+log X/0.1-X
where X is the molar conc. of both H3O+ and tricine0 at equillibrium, further solving gives X=0.082M
But I don't understand - if the pH is given to me can't I find X, which is also the H3O+ conc. at equillibrium, from 8.8=-log[H3O+]? If I do that, I'll get a very different answer to X... why is that?