Calculating Momentum with Time: A Free Fall Problem

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A 50 kg body in free fall experiences momentum that can be calculated using the formula P = mv. After 5 seconds, the velocity of the body is determined to be 49.05 m/s, assuming an initial velocity of zero. The momentum is then calculated as P = (50 kg)(49.05 m/s), resulting in a momentum of 2,452.5 kg·m/s. The discussion clarifies that the focus is on calculating momentum rather than force. The final calculation confirms the correct application of the momentum formula.
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Homework Statement


A body of mass 50 kg is allowed to fall freely under the action of gravity. Calculate the momentum it possesses after 5 seconds


Homework Equations


P=mv
F=ma


The Attempt at a Solution


I'm thinking we're really looking for how force affects momentum here? Since (F=ma) and acceleration is just how velocity changes over time would we use:
F = m * v/t
and then replace v with a =
F=(50)(9.81)/5 = 98.10 J

Is this correct?
 
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As you mentioned, momentum is defined as p = mv. v varies with t. What is the velocity of the mass during its' free fall?
 
radou said:
As you mentioned, momentum is defined as p = mv. v varies with t. What is the velocity of the mass during its' free fall?
v = vi- gt =
0-(-9.81)(5) = 49.05 m/s
this is assuming initial velocity was 0 which i don't think we can really assume.
Would we then insert that value:
F = m * v/t
F=(50)(49.05)/5 = 490.5 J
 
kriegera said:
v = vi- gt =
0-(-9.81)(5) = 49.05 m/s
this is assuming initial velocity was 0 which i don't think we can really assume.

Of course we can. :)

kriegera said:
Would we then insert that value:
F = m * v/t
F=(50)(49.05)/5 = 490.5 J

So, you got the velocity after 5 seconds right.

Now, you only need to calculate the momentum, not the force. p = mv. you have the mass, and you have the velocity after 5 seconds.
 
radou said:
Now, you only need to calculate the momentum, not the force. p = mv. you have the mass, and you have the velocity after 5 seconds.

So then we would do:
P=mv = (50)(49.05) = 2,452.5 J
correct?
 
Yes, you got it right.
 
thank you!
 
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