Calculating Multiple Images in a Plane Mirror

  • Thread starter Thread starter vu95112
  • Start date Start date
  • Tags Tags
    Mirror Plane
AI Thread Summary
In a room with two plane mirrors on opposite walls, a person standing 5 feet from the left mirror and 10 feet from the right mirror can see multiple images. The first image in the left mirror is located 10 feet behind it, while the first image in the right mirror appears 5 feet behind, resulting in a total perceived distance of 20 feet from the left mirror. The second and third images are calculated as being 30 feet and 40 feet away, respectively. Diagrams can aid in visualizing the distances and understanding the reflections. This method effectively demonstrates how multiple images are formed by plane mirrors.
vu95112
Messages
12
Reaction score
0
Plane Mirror
A person walks into a room that has, on opposite walls, two plane mirrors producing multiple images. Find the distances from the person to the first three images seen in the left-hand mirror when the person is 5ft from the mirror on the left wall and 10 ft from the mirror on the right wall.

I know the first image is 10 ft because in the plane mirror, the image is as far behind the mirror as the object is in front. I don’t know how to figure out the second and the third images? I need you help please. Thank you.

Vu95112
 
Physics news on Phys.org
Try making a diagram like that found in scrolling down the page at http://dev.physicslab.org/Document.aspx?doctype=3&filename=GeometricOptics_PlaneMirrors.xml":

It may help to keep you from getting confused. The first image in the left mirror is the virtual image of the person and as you say 10' behind the mirror. Apply the same logic to the first image in the right mirror. It would be 5' behind the mirror and since the mirrors are 15' apart, would seem to be 20' away. And so forth.
 
Last edited by a moderator:
Hello denverdoc,
Thank you very much for your help. A diagram is very useful.
The first image is 10ft
The second image is 30 ft
The third image is 40 ft

Thank you,

Vu95112
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top