Calculating Net Charge on a Spherical Conducting Shell

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A spherical conducting shell with a total charge of 10C has a -3C point charge at its center. The electric field inside the conductor is zero, leading to the conclusion that charges must reside on the inner and outer surfaces of the shell. To maintain electrostatic equilibrium, the inner surface must have a charge of +3C, countering the -3C point charge. This results in a net charge of +3C on the inner surface. The final answer is confirmed as +3C.
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Homework Statement


10C of charge are placed on a spherical conducting shell. A -3C point charge is placed at the center of the cavity. The net charge in coulombs on the inner surface of the shell is...

A. -7
B. -3
C. 0
D. +3
E. +7

Homework Equations



<br /> \oint \vec{E}\cdot d\vec{a} =\frac{Q_{enc}}{\epsilon_0}

The Attempt at a Solution



Well, I believe the E field in conducting shell is 0 and inside the cavity the field will also be zero. So, the charges must be on the inner and outer surfaces of the spherical conducting shell. It looks like I should be solving for Q(enclosed) in Gauss's law since that is the net charge but I'm not totally sure about that. I'm stuck now with what to do.
 
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roflcopter said:
Well, I believe the E field in conducting shell is 0 and inside the cavity the field will also be zero. So, the charges must be on the inner and outer surfaces of the spherical conducting shell. I'm stuck now with what to do.

I think you almost have it.

Inside the sphere there is an e-field about the point charge though. But you are right there is no field in the conductor. (If there was, the electrons would rearrange themselves wouldn't they?)

So if there is no field in the conductor ... and you draw a Gaussian surface inside the conductor around whatever charge there may be on the inner surface, and Gauss Law is the net of the charge contained inside and ... oh did I mention already that the conductor had no field? ... so doesn't that mean then ...
 


LowlyPion said:
But you are right there is no field in the conductor. (If there was, the electrons would rearrange themselves wouldn't they?)

Yes they would rearrange themselves since E would be not be 0 and so there would be a force F=qE.

Now, since E=0 in the conductor then when solving for q in Gauss's law q is equal to zero. So, there should be an equal magnitude charge on the inner surface with an opposite sign (compared to the enclosed charge from the cavity) in order to balance things out.

So the answer looks like +3.
 


roflcopter said:
So the answer looks like +3.

I think we have a Bingo here. Go claim your prize.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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