Calculating Net Charge on a Spherical Conducting Shell

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Homework Help Overview

The problem involves calculating the net charge on the inner surface of a spherical conducting shell, given a specific charge configuration: a total of 10C on the shell and a -3C point charge at the center of the cavity. The context is rooted in electrostatics and the behavior of electric fields in conductors.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the implications of the electric field being zero within the conductor and the cavity, and how this relates to charge distribution on the shell's surfaces. There is exploration of Gauss's law and the concept of enclosed charge.

Discussion Status

Participants are actively engaging with the problem, sharing insights about the behavior of electric fields in conductors and the implications for charge distribution. There is a suggestion that the charge on the inner surface must balance the enclosed charge, leading to a potential conclusion about the charge value.

Contextual Notes

Some participants question the assumptions regarding the electric field and charge distribution, indicating a need for clarity on how charges rearrange in response to electric fields within conductors.

roflcopter
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Homework Statement


10C of charge are placed on a spherical conducting shell. A -3C point charge is placed at the center of the cavity. The net charge in coulombs on the inner surface of the shell is...

A. -7
B. -3
C. 0
D. +3
E. +7

Homework Equations



[tex] \oint \vec{E}\cdot d\vec{a} =\frac{Q_{enc}}{\epsilon_0}[/tex]

The Attempt at a Solution



Well, I believe the E field in conducting shell is 0 and inside the cavity the field will also be zero. So, the charges must be on the inner and outer surfaces of the spherical conducting shell. It looks like I should be solving for Q(enclosed) in Gauss's law since that is the net charge but I'm not totally sure about that. I'm stuck now with what to do.
 
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roflcopter said:
Well, I believe the E field in conducting shell is 0 and inside the cavity the field will also be zero. So, the charges must be on the inner and outer surfaces of the spherical conducting shell. I'm stuck now with what to do.

I think you almost have it.

Inside the sphere there is an e-field about the point charge though. But you are right there is no field in the conductor. (If there was, the electrons would rearrange themselves wouldn't they?)

So if there is no field in the conductor ... and you draw a Gaussian surface inside the conductor around whatever charge there may be on the inner surface, and Gauss Law is the net of the charge contained inside and ... oh did I mention already that the conductor had no field? ... so doesn't that mean then ...
 


LowlyPion said:
But you are right there is no field in the conductor. (If there was, the electrons would rearrange themselves wouldn't they?)

Yes they would rearrange themselves since E would be not be 0 and so there would be a force F=qE.

Now, since E=0 in the conductor then when solving for q in Gauss's law q is equal to zero. So, there should be an equal magnitude charge on the inner surface with an opposite sign (compared to the enclosed charge from the cavity) in order to balance things out.

So the answer looks like +3.
 


roflcopter said:
So the answer looks like +3.

I think we have a Bingo here. Go claim your prize.
 

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