Calculating Net Electric Flux in a Cylindrical Solid of Charge - Homework Help

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SUMMARY

The net electric flux through a cylindrical Gaussian surface surrounding a solid of charge is determined using the formula for enclosed charge. Given a charge distribution of q = 12Q, radius R = 5L, length H = 6L, and a Gaussian surface with length h = 3L, the net electric flux is calculated as electric flux = (12h/H)(Q/ε0). This results in an electric flux value of 6Q/ε0, confirming that no complex equations are necessary for this calculation.

PREREQUISITES
  • Understanding of Gaussian surfaces in electrostatics
  • Familiarity with electric flux concepts
  • Knowledge of charge distribution in cylindrical coordinates
  • Basic understanding of the permittivity of free space (ε0)
NEXT STEPS
  • Study the derivation of Gauss's Law in electrostatics
  • Learn about the applications of Gaussian surfaces in different charge distributions
  • Explore the implications of electric flux in various geometries
  • Investigate the role of the permittivity of free space (ε0) in electric field calculations
USEFUL FOR

Students in physics, particularly those studying electromagnetism, educators teaching electrostatics, and anyone seeking to understand electric flux in cylindrical charge distributions.

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Homework Statement


The charge distribution in the figure to the right is a cylindrical solid of charge q, radius R, and length H. The Gaussian surface S is a cylindrical shell with radius r and length h, with r > R. Determine the net electric flux given that q = 12Q, R = 5L, H = 6L, r does not apply, and h = 3L (type the integer value, along with the sign, without typing units Q/e0):

Homework Equations


"The net electric flux will be in units of Q/e0, with e0 the permittivity of free space."
e0=8.85x10^-12

The Attempt at a Solution


have no idea how to do this. I tried q/e0 = 12/(8.85x10^-12) but its too huge value..maybe i got the wrong equation.

edit; i just got this. turns out you didn't need ANY equations at all, just common sense. its just q*(h/H) which in this case is 6 though I have no idea why this is the answer, it would just give you the enclosed charge right? you would still have to divide by e0..?
 
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asdf12312 said:

Homework Statement


The charge distribution in the figure to the right is a cylindrical solid of charge q, radius R, and length H. The Gaussian surface S is a cylindrical shell with radius r and length h, with r > R. Determine the net electric flux given that q = 12Q, R = 5L, H = 6L, r does not apply, and h = 3L (type the integer value, along with the sign, without typing units Q/e0):


Homework Equations


"The net electric flux will be in units of Q/e0, with e0 the permittivity of free space."
e0=8.85x10^-12

The Attempt at a Solution


have no idea how to do this. I tried q/e0 = 12/(8.85x10^-12) but its too huge value..maybe i got the wrong equation.

edit; i just got this. turns out you didn't need ANY equations at all, just common sense. its just q*(h/H) which in this case is 6 though I have no idea why this is the answer, it would just give you the enclosed charge right? you would still have to divide by e0..?

Yes the net charge inside the Gaussian surface is qh/H but substitute q = 12Q and then ε0*(electric flux) = qh/H. The answer thus is electric flux = 12Qh/Hε0 but the answer is to be in units of Q/ε0 so what is the answer then? Does it help if I rewrite flux = (12h/H)(Q/ε0)?
 

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