Calculating Net Magnetic Field for 3 Parallel Conductors: RHR Method Explained"

AI Thread Summary
To calculate the net magnetic field exerted by two parallel conductors on a third conductor, the Right-Hand Rule (RHR) is applied to determine the direction of the magnetic fields. For conductor #3, the magnetic field is directed out of the page, while for conductor #2, it is directed into the page. The formula for the net magnetic field should consider the distances between the conductors accurately, with the correct denominator being b+a. Clarification on the arrangement of the conductors is essential, as the position affects the direction of the fields. Understanding these relationships is crucial for accurate calculations of the magnetic field and forces involved.
EvaBugs
Messages
19
Reaction score
0
I have a small question about net magnetic field.

If I have 3 straight conductors that are parallel where
-the current is to the left in conductor #3 (and situated at a distance b from #2)
-the current is to the right in conductor #2. (and is situated at a distance a from #1)
I have to find the net magnetic field exerted by #2 and #3 on the first conductor.


Using RHR I found that:
-conductor #3 , the magnetic field is directed out of the page;
-Conductor #2, the magnetic field is into the page.


To find the net magnetic field, should I use B= KI2/(b+a) - KI2/a

Thank you in advance
 
Last edited:
Physics news on Phys.org
Are the conductors arranged in the order of number? #2 between #1 and #3? And was it supposed to say

-the current is to the left in conductor #3 (and situated at a distance b from #1)

and

I have to find the net magnetic force exerted by #2 and #3 on the first conductor
 
Last edited:
Yes, it's supposed to say that. They are placed on top of the other.
 
If I am reading it right, the denominator a+b should be b itself. Are you looking for just the magnetic field, or the force on wire #1?
 
For the net B on wire #1

-the current is to the left in conductor #3 (and situated at a distance b from #2)
-the current is to the right in conductor #2. (and is situated at a distance a from #1)
 
EvaBugs said:
For the net B on wire #1

-the current is to the left in conductor #3 (and situated at a distance b from #2)
-the current is to the right in conductor #2. (and is situated at a distance a from #1)

Then the b+a should be correct

If #1 is on top, then your field directions are reversed. If #1 is on the bottom you have them right
 
Yes, it is at the bottom

Thank you
 
Back
Top