The probability of choosing the winning number would be 1 out of the number of ordered 6-character strings you can create from a 49 character set without replacement. The latter number is what you calculated, 49 choices for the first character multiplied by 48 choices for the second character, and so on for 6 factors.whatdofisheat said:i was trying to calculate the odds of winning the lotto 6/49 6 diffrent numbers and the numbers go from 1 - 49 could anyone calculate it and show me the formula i thought it would be 49*48*47...*43 but that does not seem right
thanks
The Lotto 6/49 game is a popular lottery game in Canada where players choose 6 numbers from a pool of 1-49. If all 6 numbers match the winning numbers, the player wins the jackpot prize.
The formula for calculating the odds of winning Lotto 6/49 is n! / (k!(n-k)!), where n is the total number of possible numbers and k is the number of numbers chosen for the winning combination. In this case, n=49 and k=6, so the formula becomes 49! / (6!(49-6)!) = 13,983,816.
The probability of winning the Lotto 6/49 jackpot is 1 in 13,983,816. This means that for every ticket purchased, there is a 1 in 13,983,816 chance of winning the jackpot prize.
The odds of winning cannot be improved, as they are based on mathematical probabilities. However, buying more tickets or joining a lottery pool can increase the chances of winning, as the number of entries increases.
No, the odds of winning in Lotto 6/49 are solely based on the mathematical formula and are not affected by any external factors such as previous winning numbers or the day of the week the draw takes place.