Calculating Oil Height Between Coaxial Tubes with Dielectric Homework

  • Thread starter Thread starter SpY]
  • Start date Start date
  • Tags Tags
    Dielectrics Tube
Click For Summary
SUMMARY

The discussion focuses on calculating the height of dielectric oil between two coaxial metal tubes, where the inner tube has a potential V and the outer tube is grounded. Key equations include the electric dipole moment \vec{p} = \epsilon_0 \chi \vec{E} and the height of displacement h = \epsilon_0 (1 + \chi) \vec{E}. A critical analysis reveals that the initial approach lacked coherence, as the dipole moment and height do not share units. The solution requires a deeper understanding of the forces acting on the oil and the momentum change necessary for it to rise.

PREREQUISITES
  • Understanding of electric fields and potentials
  • Familiarity with dielectric materials and their properties
  • Knowledge of momentum and forces in physics
  • Basic grasp of electrostatics and Maxwell's equations
NEXT STEPS
  • Study the relationship between electric fields and dielectric materials
  • Learn about the principles of momentum conservation in fluid dynamics
  • Explore the concept of electric dipole moments in electrostatics
  • Investigate the forces acting on fluids in electric fields
USEFUL FOR

Students in physics, particularly those studying electromagnetism and fluid dynamics, as well as educators seeking to clarify concepts related to dielectrics and electric fields.

SpY]
Messages
63
Reaction score
0

Homework Statement


Two coaxial metal tubes (placed vertically) have an inner radius a and outer radius b. They are placed vertically between a dielectric oil (with susceptibility X and mass density p). The inner tube has potential V and the outer one is grounded (V=0). How high will the oil rise in the space between the tubes?

2. Homework Equations (and attempt at solution)

Starting with these equations is my attempt at a solution :P
[tex]\vec{p} = \epsilon_0 \chi \vec{E}[/tex]
[tex]h = \epsilon_0 (1 + \chi) \vec{E}<br /> = \epsilon_0 \vec{E} + \vec{p}[/tex]

And the permittivity is
[tex]\epsilon_0 (1 + \chi)[/tex]
[tex]h[/tex] height of displacement
[tex]\vec{p}[/tex] electric dipole moment
[tex]\chi[/tex] susceptibility
[tex]\epsilon_0[/tex] permittivity in free space
[tex]\vec{E}[/tex] electric field
 
Last edited:
Physics news on Phys.org


SpY];2914451 said:

Homework Statement


Two coaxial metal tubes (placed vertically) have an inner radius a and outer radius b. They are placed vertically between a dielectric oil (with susceptibility X and mass density p). The inner tube has potential V and the outer one is grounded (V=0). How high will the oil rise in the space between the tubes?

2. Homework Equations (and attempt at solution)

Starting with these equations is my attempt at a solution :P
[tex]\vec{p} = \epsilon_0 \chi \vec{E}[/tex]
[tex]h = \epsilon_0 (1 + \chi) \vec{E}<br /> = \epsilon_0 \vec{E} + \vec{p}[/tex]

And the permittivity is
[tex]\epsilon_0 (1 + \chi)[/tex]
[tex]h[/tex] height of displacement
[tex]\vec{p}[/tex] electric dipole moment
[tex]\chi[/tex] susceptibility
[tex]\epsilon_0[/tex] permittivity in free space
[tex]\vec{E}[/tex] electric field

This looks more like a random guess than an attempt at a solution. Dipole moment and height don't even have the same units, so, without even working out the solution, I can tell you your guess is wrong.

Instead of randomly mashing formulas together, try applying some physical laws. In order for the oil to rise (it must change its momentum to do so), what must be exerted on it (hint: it rhymes with a "met horse" )? What forces are acting on the oil? What is the rate of change of the oil's momentum when it reaches its new maximum height? What does that tell you about the net force on it?
 

Similar threads

  • · Replies 29 ·
Replies
29
Views
4K
  • · Replies 10 ·
Replies
10
Views
5K
Replies
3
Views
2K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K