Calculating Overtaking Time and Distance in One-Dimensional Motion

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To calculate the overtaking time and distance in one-dimensional motion, use the kinematic formula for position as a function of time, which is s = ut + 0.5at². For Kathy, her position starts at t = 0 with an acceleration of 4.90 m/s², while Stan, who starts 1 second earlier, has an acceleration of 3.50 m/s². It's essential to establish their initial times correctly, with Kathy's time starting at t = 0 and Stan's at t = -1 second. Determine Stan's position and speed at the moment Kathy begins her motion to set up the equations for their respective positions. This approach will help find the time, distance, and speeds at the moment of overtaking.
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Kathy Kool buys a sport car that can accelerate at the rate of 4.90 m/s2. She decides to test the car by racing with another speedster, Stan Speedy. Both start from rest, but experienced Stn leaves the starting line 1.00 s before Kathy. Stan moves with a constant acceleration of 3.50 m/s2 and Kathy maintains an accceleration of 4.90 ms2.

a) Find the time at which Kathy overtakes Stan.
b) Find the distance she travels before she catches him.
c) Find the speeds of both cars at the instant she overtakes him.

I am not asking for the solution, I just want clues to help me resolve this question. Thank you.
 
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What's the kinematic formula for position as a function of time for uniformly accelerated motion? Use that formula to describe the position of each car as a function of time.
 
Ayesh your quote is very crazy yar but i am thinking over it wait please
 
For the initial time, should I use Ti-Kathy=1 second and Ti-Stan=0 second?
 
What I would do is measure time starting at t = 0 when Kathy starts moving. Where is Stan and how fast is he moving at that time?
 

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