Calculating percent elongation and determining ductility?

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SUMMARY

The discussion focuses on calculating the percent elongation of a specimen subjected to a tensile load, specifically using the formula for percent elongation: ((Lf - Lo) / Lo) * 100. In this case, with an original length (Lo) of 165 mm and a final length (Lf) of 202 mm, the calculated percent elongation is 22.42%. This value directly represents the specimen's ductility, confirming that the calculation encompasses both concepts of elongation and ductility.

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  • Familiarity with the formula for percent elongation
  • Knowledge of material properties related to ductility
  • Basic mathematical skills for performing calculations
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Homework Statement


A specimen with an original length of 165 mm is subjected to a tensile load of 4500 N until it breaks. It’s final length is 202 mm. Calculate the specimen’s ductility in terms of percent elongation to break.

Homework Equations


((Lf - Lo) / Lo) * 100 = %EL

The Attempt at a Solution


( (202-165) / 165) * 100 = 22.42 %

I feel like I am completely wrong or still missing something. Is this percentage the specimen's ductility and the percent elongation?

Thank you,
Douglas
 
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It seems to me you did this correctly.
 
Thank you, sir.

I keep thinking of ductility as a separate calculation but it turns out this calculation covered it.
 

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