Calculating Pool Depth: An Angle of 14o

  • Thread starter Thread starter yekidota
  • Start date Start date
  • Tags Tags
    Angle Depth
AI Thread Summary
To calculate the depth of a pool filled with water, a ray of light exits at an angle of 14 degrees from the bottom left corner to the upper right side. The relevant equation used is Snell's Law, which relates the angles of incidence and refraction. The calculated angle of refraction is 10.48 degrees, leading to a depth of approximately 1.01 meters. It is clarified that the angle used for calculations should be 90 degrees minus the exit angle of 14 degrees to find the correct angle of refraction. Understanding this distinction is crucial for accurate depth calculations.
yekidota
Messages
3
Reaction score
0

Homework Statement


There is a pool 5.50 meter wide filled to the top with water, A ray of light originates at the
bottom left corner of the pool leaves the far upper right side at an angle of 14o. The question is asking for the depth of the pool



Homework Equations



n1sintheta=n2sintheta

The Attempt at a Solution



1sin14=1.33sintheta
tetha = 10.48 degree
using Tan the depth comes to 1.01m

My question is do i use 14 for the angle or do I have to do 90-14, and if yes why?
 

Attachments

  • Capture.JPG
    Capture.JPG
    7.7 KB · Views: 400
Physics news on Phys.org
You have to use (90 - 14) which is the angle of refraction.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Solve Depth of Pool w/ Snell's Law
Replies
7
Views
2K
Critical angle: find the depth of the fish looking up
Replies
4
Views
3K
Optics question - coin at the bottom of a swimming pool
Replies
1
Views
5K
Calculating the Depth of a Cylinder Using Refraction
Replies
7
Views
3K
Actual vs percieved depth. optics question
Replies
1
Views
2K
Learn how to solve optics questions with 5 degree ray angles | Homework Help
Replies
1
Views
2K
Angle of rarefraction in a pool
Replies
3
Views
2K
Optimizing Dolphin Tracking: Calculating the Angle for Dart Gun Accuracy
Replies
3
Views
2K
How Does Refraction Help Calculate the Depth of a Pool?
Replies
1
Views
2K
Working out tension of string holding a ball underwater
Replies
3
Views
4K

Hot Threads

Recent Insights

Back
Top