Calculating power absorbed in transmission lines

AI Thread Summary
The discussion focuses on calculating the power absorbed by a transmission line in an open circuit scenario, with specific parameters provided for the ABCD model. The original poster is uncertain about how to approach the problem and questions the relevance of the given constants. It is clarified that the transmission line behaves like an antenna, implying that it can radiate power even without a completed circuit. The open-circuit voltage is specified as 88.9kV, and the formulas for calculating voltage and current at the sending and receiving ends are provided. Ultimately, it is suggested that if the calculated values for voltage and current are correct, determining the power should be straightforward.
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Homework Statement


Calculate the power (Pso) absorbed from the supply by the transmission line on open circuit.

Given parameters are:

A1= 0.8698
A2= 0.03542
B1= 47.94Ω
B2= 180.8Ω
C1= 0S
C2= 0.001349S
D1= 0.8698
D2= 0.03542

I have calculated Vs and Is earlier in the question

Vs= 77325 + j3149V
Is= j119.93A

Homework Equations

The Attempt at a Solution



I don't know where to start with this one to be honest and haven't got any real direction from my course notes. Can i use equation P=I^2*R? I suspect it's more complicated than that!
 

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Ok, you clearly have not given enough here to solve the problem. What do these constants A1 etc. refer to? They don't appear on your diagram.

A transmission line can act like a big antenna. That means it has inductance and capacitance. And it can radiate power, and have current flowing even though there is no completed circuit. If you have not covered these things in class, and your text does not describe how to deal with it, you need to go to your instructor and get help.

There should be a formula that tells you how to calculate this. It will include such things as the frequency of the applied voltage.
 
Thanks DEvans,

Sorry, i should have included this information on the original post.

I have been given the open-circuit received voltage of 88.9kV and the only formulas i have for this question are:

Vs= Vr (A1+jA2) + Ir (B1+jB2)
Is= Vr (C1 + jC2) +Ir (D1 + jD2)

'S' and 'R' are for sending end and receiving end. These are what i used to calculate Vs and Is earlier in the question, although i used zero as 'Ir' due to it being open circuit (thinking no current could flow) but from what you've said above i may need to look at those answers again.

With regards A1 etc. i have no further information, this is all that is given on the assignment. Looks like i'll have to contact the tutor for this module.
 
I believe this problem has appeared earlier on PF homework help.

@DEvens, these are the ABCD 2-port parameters for the xmsn line.

If the OP got the right Vs and Is (post 1) then computing the power is straightforward.
 

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