Calculating Power Loss in Transmission Cables

AI Thread Summary
The discussion revolves around calculating power loss in transmission cables supplying a factory with 1MW of electrical power at 10KV, with a total cable resistance of 0.5 ohm. Participants clarify that the current can be calculated using the formula I = P/V, resulting in 1000A, which represents the current at the factory. The power loss in the cables is computed using the formula P_loss = I^2R, leading to a significant portion of the power being lost during transmission. The conversation also touches on how the power loss percentage would change if the supply voltage were reduced to 250V. Overall, the focus is on understanding the relationship between current, resistance, and power loss in transmission systems.
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Homework Statement



A power station supplies a factory with 1MW of electrical power at a p.d of 10KV. The total resistance of both cables between power station and factory is 0.5 ohm. Find the percentage of the power station output power which is delivered to the output factory.How does this figure change if the supply p.d s only 250V.

Homework Equations

The Attempt at a Solution


Well , i tried to find I , which is I = p/v = (106)/(103)=1000A
Then i use = I2R
And get 5*105
But i don't know if am on the right way.
 
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So, what do you think the power you now computed represents?

Also, remember to put units on your numbers.
 
Well to be honest , i don`t have a clue on how to do this question .But am trying to understand and do it.
 
So let us take things one step at a time to figure out what you have computed. In your first step, you say I = P/V. Which values did you put in here and what current does the result represent?
 
Power= 10MW
P.D =10KV

I = p/v = (106)/(103)=1000A

Well the answer represents the current at the factory ?
 
Yes, it is the current at the factory. How does this relate to the current through the cables to and from the factory?
 
Well i can calculate the power loss by using p=I2R right or p=V2/R
 
Yes. So the current through the cables must be the same as through the factory.

You do not have the voltage across the cables, so you must use the first expression. So what you computed is the power loss. How large a portion of the power from the power station does this represent?
 
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