Calculating Powers of Complex Numbers: Is My Answer Correct?

Trail_Builder
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not sure if this is in the right section as i havn't got to calculus yet lol. anyways, was wondering whether you could check i have calculated this right as I'm learning complex numbers at the moment and have no way of checking my working. thnx

Homework Statement



Calculate [tex](\surd5 - 2i)^{11}[/tex]

Homework Equations





The Attempt at a Solution



Find polar form of [tex](\surd5 - 2i)[/tex]

[tex]r = complex modulus[/tex]

[tex]r = \sqrt{5 + 4}[/tex]
[tex]r = 3[/tex]

[tex]Arg(z) = sin^{-1}(\frac{2}{3})[/tex]

sub all that into [tex]r(cosArg(z) + i*sinArg(z))[/tex]

but before actual calculate take the power of 11 into consideration so...

[tex](\surd5 - 2i)^{11} = r^{11}(11*cosArg(z) + 11i*sinArg(z))[/tex]

I then calculate all that as

[tex]177147(8.19..+7.33..i)[/tex]

[tex]1452413.3..+1299078i[/tex]



hope that's right :D

thnx
 
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The argument of a complex number (x+iy) = ?
 
ermmm, did i just work out the angle of the triangle instead of working out the angle counterclockwise from the x-axis? (on the argand diagram i think its called/complex plane)

think i might of

would the argument be instead [tex]360 - sin^{-1}(\frac{2}{3})[/tex]?
 
Why not just sin-1(-2/3)? (Admittedly, that is the same as 360- sin-1(2/3).)
 

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