Calculating Pressure Difference in Venturi Meter

Click For Summary
SUMMARY

The discussion focuses on calculating the pressure difference in a Venturi meter, specifically with a gauge pressure of 40 kPa at the inlet and a vacuum of 38 mm mercury at the throat. The fluid in the Venturi meter is oil with a relative density of 0.8. Participants emphasize the need to determine the height of the fluid column in a differential U-tube manometer, which involves summing the pressures exerted by both mercury and oil. The final answer for the difference in mercury levels is 0.359 m.

PREREQUISITES
  • Understanding of fluid mechanics principles, particularly pressure differentials.
  • Familiarity with the operation of Venturi meters.
  • Knowledge of manometer usage and calculations involving different fluids.
  • Basic understanding of relative density and its implications in fluid calculations.
NEXT STEPS
  • Study the principles of fluid dynamics related to Venturi meters.
  • Learn how to calculate pressure differences using U-tube manometers.
  • Explore the effects of fluid density on pressure measurements in mixed liquid systems.
  • Investigate the application of Bernoulli's equation in real-world fluid flow scenarios.
USEFUL FOR

Engineering students, fluid mechanics professionals, and anyone involved in the design or analysis of fluid measurement systems, particularly in applications using Venturi meters.

Bruce Dutton
Messages
2
Reaction score
0

Homework Statement



The gauge pressure at the inlet of a horizontal venturi meter is 40kPa. The vacuum at the throat is 38 mm mercury. If a differential U-tube manometer containing mercury is the U-tube and the oil in the connecting tubes is connected to the venturi, what will the difference in the mercury levels be? the fluid in the venturi meter is oil with a relative density of 0.8.
Answer [0,359m]

Homework Equations



I am bit stuck i can get the pressures of the tubes but i am having problem trying to get the levels...


The Attempt at a Solution

 
Physics news on Phys.org
Hi bruce. Do you have a picture of this? That would help. It seems like all you need to do is determine the height of a column of fluid. Granted, this is complicate by what sounds like a column of mercury plus a column of oil, but the total pressure caused by two disimilar liquids is the sum of the pressure exerted by each liquid individually.
 
I don't but what i can imagine is that the one side of the U tube would be at the opening of the venturi and the other side in the smaller tube of the venturi... well that's how i would picture it since it is dealing with different pressures... i would assume, Bruce
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
6K
  • · Replies 19 ·
Replies
19
Views
6K
  • · Replies 26 ·
Replies
26
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 9 ·
Replies
9
Views
8K