Calculating PV Panel Area and Installed Power for 3000 kWh/year Production

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To produce 3000 kWh/year with a global irradiance of 850 kWh/m^2/year and a conversion efficiency of 13%, the required PV panel area is approximately 27.15 m^2. For the installed power in kWp, it is necessary to understand that "p" refers to peak power, which is the maximum output under ideal conditions. The calculation involves determining how much energy can be generated per kilowatt peak rating, which is given as 850 kWh/kWp/year. Clarification on the process for calculating installed power is needed, as the user expresses confusion about the terminology. Understanding these concepts is crucial for effectively calculating solar panel requirements for energy production.
readaynrand

Homework Statement



a) What is the PV panel area needed to produce 3000 kWh/year when the global irradiance is 850 kWh/m^2 year, and the conversion efficiency is 13%?

b) What is the installed power in kWp that the PV panels must provide, assuming a conversion of 850 kWh/kWp year (kilowatt hours per year per kilowatt peak rating)?

2. The attempt at a solution

a) Easy peasy, A=27,15 m^2

b) No idea what I'm asked to do here... What does the p stand for?
 
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