Calculating Radius for Stone in Rotating Tire with Static Friction

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To determine the radius of the tire, the maximum centripetal force provided by static friction must be calculated using the formula F_friction = μ * FN, where μ is the coefficient of static friction (0.71) and FN is the normal force (1.8 N). This results in a maximum frictional force of approximately 1.278 N. The centripetal force required for the stone moving at 16 m/s can be expressed as F_c = (m * v^2) / r, where m is the mass of the stone (3.0 x 10^-3 kg). Setting the maximum frictional force equal to the centripetal force allows for the calculation of the radius r of the tire, leading to the conclusion that the radius can be determined through these equations.
TastyTyr
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please help...uniform circular motion..I am STUMPED:frown:

A stone has a mass of 3.0 10-3 kg and is wedged into the tread of an automobile tire, as the drawing shows. The coefficient of static friction between the stone and each side of the tread channel is 0.71. When the tire surface is rotating at 16 m/s, the stone flies out of the tread. The magnitude FN of the normal force that each side of the tread channel exerts on the stone is 1.8 N. Assume that only static friction supplies the centripetal force, and determine the radius r of the tire.
 
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Show what you've done so far. (Hint: What's the maximum possible centripetal force that the friction can supply?)
 
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