Calculating Repulsive Force Between Parallel Wires

AI Thread Summary
The discussion focuses on calculating the repulsive force between two parallel wires carrying opposite currents, using the formula F=μ₀(I²L)/(2πr). The problem involves balancing the forces acting on the wires, which include their weight and the repulsive force due to the currents. The distance between the wires is determined using trigonometric functions based on the angle of 6.00 degrees. Participants suggest breaking down the forces into their x and y components to solve the problem effectively. The conversation highlights the importance of geometry in understanding the forces at play.
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Homework Statement



[PLAIN]http://img813.imageshack.us/img813/6592/36756643.png

Homework Equations



F=\mu_0\frac{II'L}{2\pi r}

The Attempt at a Solution



The wires have a weight \lambda Lg. They require an equal but opposite force to keep them at equilibrium at 6.00 degrees. This force comes from the repulsion between the oppositely flowing currents in the wires, given by
F=\mu_0\frac{I^2L}{2\pi r}. The distance r between the two wires is sin(6.00 degrees)*0.0400 m*2.

I'm stuck at the components of the forces. Could someone give me a hint? I'm terrible at geometry.
 
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hi cdotter! :smile:
cdotter said:
I'm stuck at the components of the forces. Could someone give me a hint? I'm terrible at geometry.

hint: call the tension in each string T,

and do components of forces in the y and x directions :wink:
 
tiny-tim said:
hi cdotter! :smile:


hint: call the tension in each string T,

and do components of forces in the y and x directions :wink:

Got it, thank you.
 
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