Calculating Rolling Friction Coefficient u_r

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SUMMARY

The discussion focuses on calculating the coefficient of rolling friction (u_r) for a car rolling down a ramp. The car, starting from a height of 18.8 cm, traveled a distance of 181 cm in 2 seconds. Using the equations of motion, the user derived an initial velocity of 1.92 m/s and calculated an acceleration of -0.960 m/s², leading to a coefficient of rolling friction u_r of 0.098. The user seeks confirmation on the correctness of this calculation and guidance on how to verify the result.

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Homework Statement


Need to calculate the coefficient of rolling friction u_r. A car was set atop a ramp at a height of 18.8 cm and then rolled (not pushed) down the ramp. There is a strip of material, 3 different types including rug, sandpaper, and plexiglass, where the car is eventually stopped. The timer was started once the car reached the bottom of the ramp and went up until the car stopped. Distance was also measured. Assumptions are that frictional force is 0 up until it hits the bottom of the ramp once the time is started and that friction on the bearings is also 0.

For this specific case, the car went for 2 seconds and for a total distance of 181 cm.

Homework Equations


mgh = 1/2 mv^2
v= sqrt(2gh)

F_f = u_r*F_n
F_n = mg
F = ma
so, u_r = a/g

a = v/t

The Attempt at a Solution


Being that the height of the ramp is 18.8cm I got that the initial velocity at time 0 is 1.92m/s. I then took that velocity divided by the time to reach an acceleration of -.960m/s^2. Taking that divided by g I get that u_r = .098. Is this correct? Where would I plug in .098 to check my answer?
 
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