Engineering Calculating Rotations and Slip in an Asynchronous Motor

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To calculate the number of rotations of the rotary magnetic field in an asynchronous motor, the formula N_s = 120f/p is used, where f is the line frequency and p is the number of pole pairs. With a line frequency of 50 Hz and two pole pairs, the stator speed (N_s) can be determined. The slip is defined as s = (N_s - N_r) / N_s, where N_r is the rotor mechanical speed. The discussion emphasizes the importance of understanding these calculations to solve similar problems effectively. Overall, mastering these equations is crucial for success in related exams.
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Homework Statement


number of pole pairs p =2
line frequency f=50hz
number of rotations n=1250 1/min


Homework Equations





The Attempt at a Solution




question is number of rotations of the rotary magnetic field (1/min units)
the slip of the machine(s)
the frequency of the rotor current ?


please help me to solve this kind of problems i have like 5 more questions which is smilar to this one so i can learn how to solve others thank you from now good luck at your exams :)
 
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If you have the line frequency and the number of pole pairs, you can get the rotation of the stator Ns by using

N_s = \frac{120f}{p}

where f is the line frequency and p is the number of poles.

How is slip defined?
 
s = Ns-Nr/Ns Ns is stator electrical speed, and Nr is rotor mechanical speed. thank you for your helps sir.
 
Marketgirl said:
s = Ns-Nr/Ns Ns is stator electrical speed, and Nr is rotor mechanical speed. thank you for your helps sir.

Right, so using the formula I gave you above, you can get Ns. They gave you the value of Nr, so can you get the slip?
 
yes sir your help was enough, i wish you best of luck and thank you so much.
 

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